The Moore-Penrose inverse of a factorization
In this paper, we consider the product of matrices $PAQ$, where $A$ is von Neumann regular and there exist $P^{\prime }$ and $Q^{\prime }$ such that $P^{\prime }PA=A=AQQ^{\prime }$. We give necessary and sufficient conditions in order to $PAQ$ be Moore-Penrose invertible, extending known characteriz...
Autor principal: | |
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Formato: | article |
Idioma: | eng |
Publicado em: |
2003
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Assuntos: | |
Texto completo: | http://hdl.handle.net/1822/3237 |
País: | Portugal |
Oai: | oai:repositorium.sdum.uminho.pt:1822/3237 |
Resumo: | In this paper, we consider the product of matrices $PAQ$, where $A$ is von Neumann regular and there exist $P^{\prime }$ and $Q^{\prime }$ such that $P^{\prime }PA=A=AQQ^{\prime }$. We give necessary and sufficient conditions in order to $PAQ$ be Moore-Penrose invertible, extending known characterizations. Finally, an application is given to matrices over separative regular rings. |
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